hi Guys, I am facing a problem in getting the handle for a given form.I am trying to call an Axpata WINAPI::showWindow(int hd,int stat).I called this method by the following ways:
WINAPI::showWindow(this.handle(),2); WINAPI::showWindow(element.handle(),2); WINAPI::showWindow(element.design.handle(),2); WINAPI::showWindow(element.hwnd(),2); BUT non of them works.However I used the same first call in Delphi and it works just fine..?! Any Suggestions? THanks, Absi. ------------------------ Yahoo! Groups Sponsor --------------------~--> Has someone you know been affected by illness or disease? Network for Good is THE place to support health awareness efforts! http://us.click.yahoo.com/Rcy2bD/UOnJAA/cosFAA/kGEolB/TM --------------------------------------------------------------------~-> Sharing the knowledge on Axapta. Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/Axapta-Knowledge-Village/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
