Yes, with dictfield you can do so. Or with the function fieldpname(table, field).
Raúl Llorente Peña
Análisis, Desarrollo e Implementación en
Microsoft Bussiness Solutions-Axapta
OPEN SOLUTIONS
| "nabilwilson"
<[EMAIL PROTECTED]>
Enviado por: Axapta-Knowledge-Village@yahoogroups.com 18/05/2005 20:49
|
|
Excellent!
Thank you very much for help!
Another question, is there possibility to get out
the labels of the fields?
--- In Axapta-Knowledge-Village@yahoogroups.com, Raul Llorente
Peña/OPENSOLUTIONS <[EMAIL PROTECTED]> wrote:
Try this!! (you put a wrong parameter!!)
// CODE EXAMPLE
static void Job1(Args _args)
{
dictTable dt;
int numberOfFields;
int fieldId;
int i;
str table;
;
table = 'inventtable';
dt = new dictTable(tablename2id(table));
numberOfFields = dt.fieldCnt();
for (i = 1; i <= (numberOfFields); i++)
{
fieldId = dt.fieldCnt2Id(i);
//info(dt.fieldName(i));
info(dt.fieldName(fieldId));
}
}
^_^
Raúl Llorente Peña
Análisis, Desarrollo e Implementación en
Microsoft Bussiness Solutions-Axapta
OPEN SOLUTIONS
[EMAIL PROTECTED] escribió: -----
Para: Axapta-Knowledge-Village@yahoogroups.com
De: "nabilwilson" <[EMAIL PROTECTED]>
Enviado por: Axapta-Knowledge-Village@yahoogroups.com
Fecha: 16/05/2005 16:10
Asunto: [Axapta-Knowledge-Village] DictTable fieldname UNKNOWN?
Hello all,
I try to get a list from fieldnames of the
table. Following example does it, but for
some reason some fields are shown as
'UNKNOWN'. In example I use inventtable.
If I create a totally new table,
and run the code for it, then all
the names of this new table are shown
as UNKNOWN.
Does anyone an idea have what is causing this?
// CODE EXAMPLE
static void Job1(Args _args)
{
dictTable dt;
int numberOfFields;
int fieldId;
int i;
str table;
;
table = 'inventtable';
dt = new dictTable(tablename2id(table));
numberOfFields = dt.fieldCnt();
for (i = 1; i <= (numberOfFields); i++)
{
fieldId = dt.fieldCnt2Id(i);
info(dt.fieldName(i));
}
}
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