[EMAIL PROTECTED] wrote:
In 14.661 Schaums claims:
integral acoth(x/a) = x*acoth(x)+a/2*log(x^2-a^2)
^^^^^^^^
Axiom claims
integral acoth(x/a) = x*acoth(x/a)+a/2*log(x^2-a^2)
^^^^^^^^^^
Is this a Schaums typo?
Tim
_______________________________________________
Axiom-developer mailing list
Axiom-developer@nongnu.org
http://lists.nongnu.org/mailman/listinfo/axiom-developer
My schaums is the same as your Schaums but it is old (not as old as
yours) I have a New Schaums at work But I will not Be in to work today :-)
My Maxima agrees with Axium.
integrate(acoth(x/a),x);
(%o8) (a*log(x^2/a^2-1))/2+x*acoth(x/a)
_______________________________________________
Axiom-developer mailing list
Axiom-developer@nongnu.org
http://lists.nongnu.org/mailman/listinfo/axiom-developer
