Hi. Is there any way to obtain the decomposition in simple elements (don't know exactly how to say this in english) of a fraction of the form :
1 ------------------- (1-X)(1-X^2)(1-X^5) (to obtain its formal series equivalent \sum a_nX^n, a_n being the number of ways to pay n€ using 1, 2 and 5€ corners (no, there is no such thing as a 5€ corner, but there's a 5€ banknote !)). I'd like to obtain the C-decomposition, what do I have to do ? More precisely : is there a way to force the use of an extension of Q(X), by adding roots like exp(2*I*PI/5) or sqrt(2) ? \bye PS : clearly I'm not very good at using Axiom documentation ! -- Nicolas FRANCOIS | /\ http://nicolas.francois.free.fr | |__| X--/\\ We are the Micro$oft. _\_V Resistance is futile. You will be assimilated. darthvader penguin _______________________________________________ Axiom-math mailing list Axiom-math@nongnu.org http://lists.nongnu.org/mailman/listinfo/axiom-math