No, you don't have to do it manually. Just make sure that your WSDL correctly reflects the structure of MyException. I found that java2wsdl tool somehow misses the structure of application-specific exceptions. To get hold of the exception use try-catch mechanism. Note that MyException should subclass AxisFault.
If you still have problems then let me know so that I can send you a sample code. I hope that helps. Sunil Kothari ----- Original Message ----- From: Mariano Eloy Fernández <[EMAIL PROTECTED]> Date: Wednesday, February 23, 2005 1:45 pm Subject: Re: How do I deserialize the detail field in AxisFault to build MyException? > Hi, > > Some additional notes. > The XML comes in a protected attrbute called faultDetails, > inaccesible.The public detail field is null. > The question stands, How do I build MyException from this AxisFault? > > Thanks, > > Mariano. > > Mariano Eloy Fernández wrote: > > > Hello, > > > > I am working with Axis 1.1 > > I have a class MyException extends Exception thrown in the Web > > Service. Both De/Serializer are provided for MyException. > > An AxisFault is received in the client with MyException as an > XML in > > the detail field of AxisFault. > > How do I build MyException from that XML? Do I have to do it > manually? > > Then what's the MyExceptionDe/Serializer for? > > > > Thanks, > > > > Mariano Eloy Fernández. > > > >
