How about java.util.zip.ZipInputStream(actualDH.getInputStream());
Best regards, Guenter > -----Original Message----- > From: Antony Grinyer [mailto:[EMAIL PROTECTED] > Sent: Wednesday, October 12, 2005 6:42 PM > To: axis-user@ws.apache.org > Subject: Newbie: Recreating Zip file in MTOM service class? > > Hi, > > Being an axis2 newbie, I've managed to create an MTOM client and > service, passing a Zip file to the service, however I'm unsure what to > do at the service end to recreate the zip? The example on the axis2 > website just shows what to do with an image. Here's snippets > of my code: > > CLIENT: > > << snip >> > > OMElement zip = fac.createOMElement("zip", omNs); > > File file = new File(filePath); > > byte[] bytes = new byte[(int)file.length()]; > bytes = BDBXMLUtils.getBytesFromFile(file); > ByteArrayDataSource dataSource = new ByteArrayDataSource(bytes); > dataHandler = new DataHandler(dataSource); > OMText textData = fac.createText(dataHandler, true); > zip.addChild(textData); > > << snip >> > > The do all the client calls to the addDocumentsAsZip web > service method. > > SERVICE: > > public OMElement addDocumentsAsZip(OMElement element) > throws XMLStreamException > { > OMFactory fac = OMAbstractFactory.getOMFactory(); > OMNamespace omNs = > fac.createOMNamespace("http://some.namespace/anything";, "anything"); > > OMElement zipEle = element.getFirstElement(); > OMElement zipName = (OMElement) zipEle.getNextSibling(); > OMText binaryNode = (OMText) zipEle.getFirstChild(); > String fileName = zipName.getText(); > > DataHandler actualDH = (DataHandler)binaryNode.getDataHandler(); > > // Now, how do I get the data back into a zip? > > << snip >> > > I know there's the Java util.zip package but how do I recreate my zip > from the DataHandler? > > Any help gratefully appreciated. > Thanks, > Antony > > >
