Any solutions for the below problem. I'm kind of stuck with this.
Thanks Raghu ________________________________ From: Raghu Upadhyayula [mailto:[EMAIL PROTECTED] Sent: Tuesday, October 23, 2007 3:14 PM To: axis-user@ws.apache.org Subject: [Axis2] Problem with soap:address location in the WSDL (IP Address is not a public IP that is accessible from Internet). Hi, I have a problem with the soap:address location generated when I browse the WSDL in the browser. I'm using Axis2 1.3. I'm looking at the WSDL in the browser using http://ws.qa.company.com/webservices/services/MyWSService?wsdl I get the WSDL and the soap:address location in the WSDL looks like <soap:address location=http://10.5.2.182:80/webservices/services/MyWSService <http://10.5.2.182/webservices/services/MyWSService> /> But then problem is with the IP Address coming in the soap:address location 10.5.2.182 is not a public IP that is accessible from Internet. What changes should I do to change the soap:address location to look like <soap:address location=http://ws.qa.company.com/webservices/services/MyWSService <http://ws.qa.company.com/webservices/MyWSService> /> Another thing, I found is that this is working fine if I use ?wsdl2 in the URL above. Note: In my services.xml I have useOriginalWSDL property set to true and modifyUserWSDLPortAddress was also set to true. I've tried changing modifyUserWSDLPortAddress to false, but what happened in that case was the soap:address location was not modified at all. The soap:address location case as http://localhost:80/webservices/services/MyWSService <http://localhost/webservices/services/MyWSService> because the original WSDL had this address in the soap:address location, since the localhost was coming as it, I've change the modifyUserWSDLPortAddress property back to true. Thanks in Advance. Raghu
