On Fri, 14 Oct 2011 11:30:10 -0500
Larry Finger <[email protected]> wrote:

> I am pretty sure that the compiler would optimize out the entire htol16_buf 
> routine. After substitution for cpu_to_le16() on a little-endian system, the 
> statement in the while loop becomes '*(buf + size) = *(buf + size)', which is 

(There also is cpu_to_le16s(). Just for the record.)

-- 
Greetings, Michael.

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