Hi.
iuyoiuy oiuyiuyi:
> I'm performing an XSLT transform on a Document Node obtained from an
> SVGGraphics2D. My problem is that I can't seem to be able to match
> nodes without using local-name() in my XPATH expressions. Here's the
> Java:
>
> SVGGraphics2D svg = createMySVG();
> Document doc = (Document)svg.getDOMFactory();
> Element root = doc.getDocumentElement();
> svg.getRoot(root);
> transformer.transform( new DOMSource(root.getOwnerDocument()), new
> StreamResult(writer));
>
> And that works, except that in my XSLT I can't say:
>
> <xslt:template match="g">
>
> ...instead I have to say:
>
> <xslt:template match="*[local-name()='g']">
>
> Naturally I've tried various namespace declarations without success, knowing that
> the problem must be to do with my namespace declarations, which are:
>
> <xslt:transform
> version="1.0"
> xmlns:xslt="http://www.w3.org/1999/XSL/Transform";
> xmlns:xlink="http://www.w3.org/1999/xlink";
> xmlns:svg="http://www.w3.org/2000/svg";>
You need to remember that in XSLT 1, the XPath expressions will not use
any default namespace. You will need to explicitly mention the svg
namespace, with
<xslt:stylesheet
xmlns:svg="http://www.w3.org/2000/svg";
...>
<xslt:template match="svg:g">
</xslt:template>
...
Hope this helps,
Cameron
--
Cameron McCormack
| Web: http://mcc.id.au/
| ICQ: 26955922
---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
