Question -- Now that you've laid it out, I understand what the expression does, except for the \1 at the end of the search pattern. What does that do?
Thanks again! John On Nov 10, 9:22 am, John Gold <j...@pointseast.com> wrote: > Hey -- thank you very much. I'll give that a try! > > John > > On Nov 10, 1:33 am, Alex Satrapa <gr...@goldweb.com.au> wrote: > > > > > > > > > On 10/11/2011, at 09:23 , John Gold wrote: > > > > 1 4:09 AM 17.6 H > > > 1 10:30 AM 2.3 L > > > 1 4:34 PM 16.8 H > > > 1 10:52 PM 2.3 L > > > 2 5:02 AM 17.3 H > > > 2 11:24 AM 2.5 L > > > 2 5:30 PM 16.3 H > > > 2 11:45 PM 2.7 L > > > 3 5:56 AM 17.3 H > > > 3 12:20 PM 2.5 L > > > 3 6:26 PM 16.2 H > > > My first attempt: > > > Find: ^(\d+)(.*)\r\1 > > Replace with: \1\2\t\1 > > > This will require a couple of passes since it matches the lines by pairs. > > > Hope this helps! > > Alex > > > smime.p7s > > 2KViewDownload -- You received this message because you are subscribed to the "BBEdit Talk" discussion group on Google Groups. To post to this group, send email to bbedit@googlegroups.com To unsubscribe from this group, send email to bbedit+unsubscr...@googlegroups.com For more options, visit this group at <http://groups.google.com/group/bbedit?hl=en> If you have a feature request or would like to report a problem, please email "supp...@barebones.com" rather than posting to the group. Follow @bbedit on Twitter: <http://www.twitter.com/bbedit>
