Hi there, i have a rather "simple" grep problem. I would like to add a zero between 2 strings and cannot figure out how to write the replacement pattern.
Say, the line is foobar My regex find is (foo)(bar) So: How to escape the "0" to get "bar0foo"? \20\1 is obviously wrong. Yours Tom -- This is the BBEdit Talk public discussion group. If you have a feature request or would like to report a problem, please email "supp...@barebones.com" rather than posting to the group. Follow @bbedit on Twitter: <http://www.twitter.com/bbedit> --- You received this message because you are subscribed to the Google Groups "BBEdit Talk" group. To unsubscribe from this group and stop receiving emails from it, send an email to bbedit+unsubscr...@googlegroups.com. To post to this group, send email to bbedit@googlegroups.com. Visit this group at https://groups.google.com/group/bbedit.
