On 3/16/22 at 2:06 PM, thepo...@gmail.com (ThePorgie) wrote:
I was tinkering with with Patrick's question
Not actually my question ;-) though close enough for the matters
at hand.
So I was looking at this and knew it would have to be several
passes, but my pattern I was working with for the first pass
was "(?P<foo>\d+\.)1"
My question is since I can't use a replace pattern \1 follow by 33
You can in fact do this by prefixing a zero "0" to the singular
backreference number, so:
Replace: \0133
will give you the first backreference \01 followed by the string "33".
I was using a named pattern, but (?P=foo) doesn't call the named pattern
in the replace area of a grep search? Just curious as I couldn't find
anything regarding this in the manual.
Please see the section titled "Subpatterns Make Replacement
Powerful" in Chapter 8 (page 202) of the current manual:
Pattern Inserts
=====================================================
[...]
\P<NAME> the text matched by the subpattern NAME
Regards,
Patrick Woolsey
==
Bare Bones Software, Inc. <https://www.barebones.com/>
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