Sorry I did not finish the thing and got posted accidentally
For example, I have two thread sharing a global shared memory variable as
below. The variable shmPtr->status is protected with mutex lock in both the
function. Though there is a sleep(1/2) between mutex lock inside "for loop"
in the task1 function , I could not access the shmPtr->status in task2 when
required and have to wait until "for loop" exit in the task1 function, this
takes around 50 seconds to take control of shmPtr->status by the task2
function.
I am wondering why the task1 function is not releasing the mutex lock even
with an sleep(1/2).
thr_id1 = pthread_create ( &p_thread1, NULL, (void *)execution_task1, NULL
);
thr_id2 = pthread_create ( &p_thread2, NULL, (void *)execution_task2, NULL
);
void execution_task1()
{
for(int i = 0;i < 100;i++)
{
//100 lines of application code running here
pthread_mutex_lock(&lock);
shmPtr->status = 1; //shared memory variable
pthread_mutex_unlock(&lock);
sleep(1/2);
}
}
void execution_task2()
{
//100 lines of application code running here
pthread_mutex_lock(&lock);
shmPtr->status = 0; //shared memory variable
pthread_mutex_unlock(&lock);
sleep(1/2);
}
Regards,
NK
On Thursday, September 3, 2020 at 12:55:48 PM UTC+5:30 Niresh wrote:
> Hi,
>
> I am using beagle Bone Black with debian image. Could any please suggest
> how to optimize the application code using pthread_mutex_lock. Let me
> describe the solution I am looking at.
>
> For example, I have two thread sharing a global shared memory variable as
> below
>
> thr_id1 = pthread_create ( &p_thread1, NULL, (void *)execution_task1, NULL
> );
> thr_id2 = pthread_create ( &p_thread2, NULL, (void *)execution_task2, NULL
> );
>
> void execution_task1()
> {
>
> for(int i = 0;i < 100;i++)
> {
> pthread_mutex_lock(&lock);
> shmPtr->status = 1;
> pthread_mutex_unlock(&lock);
> sleep(1/2);
> }
> }
>
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