--- Rajeev Rumale <[EMAIL PROTECTED]> wrote:
> Thanks Dwalu,
>
> But the what i need is the grep the name of the sub which is calling the
> loging sub.
> As you have suggested "caller" only gives only the name of current sub
> routine that is &debugLogger it self.
> And I had to do call the "caller" before calling the "debugLogger" and pass
> all the info to it.
>
> What i need is the the name of the sub rotuine which is "calling" the sub
> "&debuLogger".
Pass it as an argument:
sub someSub{
statement 1;
statement 2;
statement 3;
&debugLogger($message, (caller(0))[3]);
&anotherSub;
}
sub anotherSub{
statement 1;
statement 2;
statement 3;
&debugLogger($message, (caller(0))[3]);
}
sub debugLogger {
my ( $message, $sub_name ) = @_;
open (LOGGER, ">> my.log") || die " unable to ope the log file";
print LOGGER "\n----------------------------------------";
print LOGGER "\nCalled from $sub_name.";
print LOGGER "\n$message";
print LOGGER "\n----------------------------------------";
close LOGGER;
}
Cheers,
Curtis Poe
=====
Senior Programmer
Onsite! Technology (http://www.onsitetech.com/)
"Ovid" on http://www.perlmonks.org/
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