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Today's Topics:
1. Question about Regular expression pattern consuming.
(S. H. Aegis)
----------------------------------------------------------------------
Message: 1
Date: Sun, 28 Jul 2013 18:35:27 +0900
From: "S. H. Aegis" <shae...@gmail.com>
To: "beginners@haskell.org" <beginners@haskell.org>
Subject: [Haskell-beginners] Question about Regular expression pattern
consuming.
Message-ID:
<CAJp-NqwaSkR9VQRqrU0Q=ydunnxz+eqqm_stcdyyv8hqy+l...@mail.gmail.com>
Content-Type: text/plain; charset="utf-8"
Hi.
I'm newbie to Haskell.
I want to get date, it's type is [[String]].
The problem is that "the string that is used in regular expression pattern"
is consumed. ie, disappear.
Here is my code.
------------------------------------------------------------
import Text.Regex
import Control.Applicative
main :: IO()
main = do
myIn <- readFile "Data.dat"
print $ lines <$> intoEachPt myIn
intoEachPt :: String -> [String]
intoEachPt = splitRegex (mkRegex "20[0-9]{13}AH021")
-----------------------------------------------------------
How can I fix this?
Data:
....there is many DIGIT.....201306000300001AH02112361640
9.......
Output:
[[....there is many DIGIT..."],["12361640 9......]....]
I hope:
[[....there is many DIGIT..."],["201306000300001AH02112361640
9......]....]
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