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Today's Topics:
1. Re: best performance with foldl (David Johnson)
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Message: 1
Date: Sun, 6 Oct 2013 08:28:39 -0500
From: David Johnson <[email protected]>
To: The Haskell-Beginners Mailing List - Discussion of primarily
beginner-level topics related to Haskell <[email protected]>
Subject: Re: [Haskell-beginners] best performance with foldl
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<CAAWB79h7FVSKG903FQUUJC=ygfc0kxja1fbqlca+wxx0nvf...@mail.gmail.com>
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Roland, in this case using the strict version of foldl' would give you
better performance, but to really reach C speed equivalence, I would check
out the vector package and read the stream fusion article.
Here is an example that fits your scenario:
https://gist.github.com/dmjio/6166076
On Sun, Oct 6, 2013 at 6:38 AM, Roland Lei?a <[email protected]>wrote:
> Hi all,
>
> for a benchmark I'd like to write code like this:
> foldl (+) [0 100000000]
>
> how do I get the best performance out of it? However, It is important for
> me
> to rely on a higher-order function. Is it possible to be en par with the C
> version?
> int64_t result = 0;
> for (int64_t i = 0; i <= 100000000; ++i)
> result += i;
>
> Many thanks in advance for helping out,
> Roland
>
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>
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