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Today's Topics:
1. Re: can I use "pure" all the time instead of "return" now?
(Alex Belanger)
2. Re: can I use "pure" all the time instead of "return" now?
(Imants Cekusins)
3. Re: can I use "pure" all the time instead of "return" now?
(Alex Belanger)
4. Re: can I use "pure" all the time instead of "return" now?
(Imants Cekusins)
5. Re: can I use "pure" all the time instead of "return" now?
(Anton Felix Lorenzen)
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Message: 1
Date: Mon, 16 May 2016 08:18:22 -0400
From: Alex Belanger <[email protected]>
To: The Haskell-Beginners Mailing List - Discussion of primarily
beginner-level topics related to Haskell <[email protected]>
Subject: Re: [Haskell-beginners] can I use "pure" all the time instead
of "return" now?
Message-ID:
<cadsky2y7anjokjv2mpqkrkk4fts+cwfdvp0gjupyn15fh2o...@mail.gmail.com>
Content-Type: text/plain; charset="utf-8"
(%%) is a binary function.
return and pure are both unary.
I'm don't see how the infix (%%) is solving anything here.
On May 15, 2016 6:32 PM, "Imants Cekusins" <[email protected]> wrote:
> why not use (%%) as alias for both pure and return?
>
> % - as in "investment return"
> % - as in "pure distilled .. "
>
> :-P
> ?
>
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Message: 2
Date: Mon, 16 May 2016 16:19:55 +0200
From: Imants Cekusins <[email protected]>
To: The Haskell-Beginners Mailing List - Discussion of primarily
beginner-level topics related to Haskell <[email protected]>
Subject: Re: [Haskell-beginners] can I use "pure" all the time instead
of "return" now?
Message-ID:
<cap1qinaisx8qx9vn55dt6y31hgsrrlnsetwucqjvytrypfa...@mail.gmail.com>
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> Alex
here is what I tried:
(%%):: Applicative f => a -> f a
(%%) = pure
test::Int -> IO Int
test i0 = (%%) $ i0 + (2::Int)
seems to work..
I can't get %% to work without ()
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Message: 3
Date: Mon, 16 May 2016 10:25:14 -0400
From: Alex Belanger <[email protected]>
To: The Haskell-Beginners Mailing List - Discussion of primarily
beginner-level topics related to Haskell <[email protected]>
Subject: Re: [Haskell-beginners] can I use "pure" all the time instead
of "return" now?
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<CADSky2yhWqaM3O3Ag3=jhc2-lpvvkoq+sb0fg3tdj4ozxw5...@mail.gmail.com>
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Correct, you're stuck always writing it with the parenthese because without
them; you get an infix function which is binary, not unary.
I still don't see what your solution brings new to the table in relevance
to the question. It's just trading a poorly named function for arguably an
even worse.
On May 16, 2016 10:20 AM, "Imants Cekusins" <[email protected]> wrote:
> > Alex
>
> here is what I tried:
>
> (%%):: Applicative f => a -> f a
> (%%) = pure
>
>
> test::Int -> IO Int
> test i0 = (%%) $ i0 + (2::Int)
>
>
> seems to work..
>
> I can't get %% to work without ()
>
> _______________________________________________
> Beginners mailing list
> [email protected]
> http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners
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Message: 4
Date: Mon, 16 May 2016 16:30:54 +0200
From: Imants Cekusins <[email protected]>
To: The Haskell-Beginners Mailing List - Discussion of primarily
beginner-level topics related to Haskell <[email protected]>
Subject: Re: [Haskell-beginners] can I use "pure" all the time instead
of "return" now?
Message-ID:
<cap1qinzpskm4opkte-aw1tjjf4ehaocbwkceh5lxjxsljlj...@mail.gmail.com>
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just an idea.
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Message: 5
Date: Mon, 16 May 2016 17:08:08 +0200
From: Anton Felix Lorenzen <[email protected]>
To: The Haskell-Beginners Mailing List - Discussion of primarily
beginner-level topics related to Haskell <[email protected]>
Subject: Re: [Haskell-beginners] can I use "pure" all the time instead
of "return" now?
Message-ID: <[email protected]>
Content-Type: text/plain; charset=windows-1252; format=flowed
Of course,
it doesn't solve anything, but..
{-# LANGUAGE PostfixOperators #-}
import Control.Applicative
(%%) :: Applicative f => a -> f a
(%%) = pure
go :: IO Int
go = (12 %%)
main = do
num <- (12 %%)
print num
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