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You can reach the person managing the list at beginners-ow...@haskell.org When replying, please edit your Subject line so it is more specific than "Re: Contents of Beginners digest..." Today's Topics: 1. Howto reverse a Data.Array (Timothy Washington) ---------------------------------------------------------------------- Message: 1 Date: Thu, 23 Jun 2016 00:58:24 -0700 From: Timothy Washington <twash...@gmail.com> To: The Haskell-Beginners Mailing List - Discussion of primarily beginner-level topics related to Haskell <Beginners@haskell.org> Subject: [Haskell-beginners] Howto reverse a Data.Array Message-ID: <CAADtM-aLuBffgzFYE6Mq=STRjJG9cDccc8JiLfnvO=bhvy6...@mail.gmail.com> Content-Type: text/plain; charset="utf-8" I'm still trying to get an intuitive understanding of Haskell's Data.Array <http://hackage.haskell.org/package/array-0.5.1.1/docs/Data-Array.html#g:5>, in contrast to Data.List or Data.Vector. I very much want a nested array (a matrix), where the parent list (or rows) are reversed. But neither *A.array* nor *A.istArray* allow indicies to be reversed in their constructors, nor the list comprehensions that generate the elements The only reason I'm using an array, is for the *A.//* function (operating on a matrix). Otherwise, I'd use Data.Vector <https://hackage.haskell.org/package/vector-0.11.0.0/candidate/docs/Data-Vector.html> which does have a reverse function, but a less powerful *V.//* , that doesn't accept coordinates in a matrix. Can I reverse a Data.Array? If not, then why. Thanks Tim -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://mail.haskell.org/pipermail/beginners/attachments/20160623/86086518/attachment-0001.html> ------------------------------ Subject: Digest Footer _______________________________________________ Beginners mailing list Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners ------------------------------ End of Beginners Digest, Vol 96, Issue 14 *****************************************