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Today's Topics:
1. Re: Semigroup Instances (Atrudyjane)
----------------------------------------------------------------------
Message: 1
Date: Mon, 06 Feb 2017 22:53:49 -0500
From: Atrudyjane <atrudyj...@protonmail.com>
To: Theodore Lief Gannon <tan...@gmail.com>
Cc: The Haskell-Beginners Mailing List - Discussion of primarily
beginner-level topics related to Haskell <beginners@haskell.org>
Subject: Re: [Haskell-beginners] Semigroup Instances
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Thank you Theodore. Yes, changing the variable names makes it clearer. Also the
fact that only failures are combined on the right hand side...
Regards,
Andrea
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-------- Original Message --------
Subject: Re: [Haskell-beginners] Semigroup Instances
Local Time: February 6, 2017 5:56 PM
UTC Time: February 6, 2017 11:56 PM
From: tan...@gmail.com
To: Atrudyjane <atrudyj...@protonmail.com>, The Haskell-Beginners Mailing List
- Discussion of primarily beginner-level topics related to Haskell
<beginners@haskell.org>
Gmail put you in spam.
If you haven't figured this out since you asked -- it's a matter of confusing
(IMO bad) variable names. Check the data definition:
data Validation a b
= Failure a
| Success b
deriving (Eq, Show)
Failures are always type a, and successes are always type b. The type variables
used in the first line correspond to these. But in the definitions of (<>),
they are just local values. The instance could be rewritten like so:
instance Semigroup a => Semigroup (Validation a b) where
Success x <> Success y = Success x
Failure x <> Success y = Success y
Success x <> Failure y = Success x
Failure x <> Failure y = Failure (x <> y)
On Thu, Jan 26, 2017 at 1:55 PM, Atrudyjane <atrudyj...@protonmail.com> wrote:
I'm currently studying semigroups and trying to figure out how to determine
which type variables need a semigroup instance. Here are a couple of examples
from Evan Cameron's github
(https://github.com/leshow/haskell-programming-book/blob/master/src/Ch15ex.hs):
(1)
data Validation a b
= Failure a
| Success b
deriving (Eq, Show)
instance Semigroup a => Semigroup (Validation a b) where
Success a <> Success b = Success a
Failure a <> Success b = Success b
Success a <> Failure b = Success a
Failure a <> Failure b = Failure (a <> b)
* Why doesn't 'b' need an instance of semigroup?
(2)
newtype AccumulateRight a b = AccumulateRight (Validation a b) deriving (Eq,
Show)
instance Semigroup b => Semigroup (AccumulateRight a b) where
AccumulateRight (Success a) <>AccumulateRight (Failure b) =AccumulateRight
(Success a)
AccumulateRight (Failure a) <>AccumulateRight (Success b) =AccumulateRight
(Success b)
AccumulateRight (Failure a) <>AccumulateRight (Failure b) =AccumulateRight
(Failure a)
AccumulateRight (Success a) <> AccumulateRight (Success b) = AccumulateRight
(Success (a <> b))
* Why doesn't 'a' need an instance of semigroup?
Thank you,
Andrea
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