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Today's Topics:
1. How to get IO String from Network.Socket.ByteString.recv
method (Dinesh Amerasekara)
----------------------------------------------------------------------
Message: 1
Date: Sun, 20 May 2018 07:52:33 +0000 (UTC)
From: Dinesh Amerasekara <[email protected]>
To: [email protected]
Subject: [Haskell-beginners] How to get IO String from
Network.Socket.ByteString.recv method
Message-ID: <[email protected]>
Content-Type: text/plain; charset="utf-8"
Hi,
I am unable to compile the below code.
import Network.Socket hiding(recv) import Network.Socket.ByteString as S (recv)
import qualified Data.ByteString.Lazy.Char8 as Char8
getMessage :: Socket -> IO String getMessage sock = Char8.unpack <$> S.recv
sock 8888
It gives the below error.
Couldn't match type ‘Data.ByteString.Internal.ByteString’
with ‘ByteString’NB: ‘ByteString’ is defined in ‘Data.ByteString.Lazy.Internal’
‘Data.ByteString.Internal.ByteString’ is defined in
‘Data.ByteString.Internal’ Expected type: IO ByteString Actual type: IO
Data.ByteString.Internal.ByteString
In the second argument of ‘(<$>)’, namely ‘recv sock 8888’In the expression:
unpack <$> recv sock 8888In an equation for ‘getMsg’: getMsg sock = unpack
<$> recv sock 8888
Can somebody tell me how I can return the IO String using
Network.Socket.ByteString.recv?
Best Regards,Dinesh.
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