Try:
if(exists($hash{s}) and $hash{s} ne "T" __and__ $hash{s} ne "F") {
(underscore for emphasis, not code). Using the 'or' means that if $hash{s}
is "T", ($hash{s} ne "F") is actually true, so it continues with that block.
Cheers
Mark C
-----Original Message-----
From: Charles Lu [mailto:[EMAIL PROTECTED]]
Sent: 13 June 2001 15:53
To: [EMAIL PROTECTED]
Subject: Unexplainable behavior
The following snippet of code doesn't behave the way I want it to. Yet i
cannot see why?
$hash{s} = "T";
if(exists($hash{s}) and $hash{s} ne "T" or $hash{s} ne "F") {
print "inside\n";
}
else{ print "outside\n"; }
the OUTPUT of this program prints "inside". But I want it to go INSIDE
only if the key "s" exists in the hash, AND the value of $hash{s} DOES NOT
equal "T" OR "F". Can anyone suggest what I might be doing wrong here?
By the way, even if I comment out the line that contain
$hash{s} = "T";, the output still goes to "INSIDE".
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