On Wed, Jun 27, 2001 at 06:21:30PM +0200, Paul Johnson ([EMAIL PROTECTED]) spew-ed forth:
> On Wed, Jun 27, 2001 at 11:07:12AM -0400, Kevin Meltzer wrote:
> >
> > Is that the reason? I would think --'a' would be z, but that is my own
> > internal logic :)
>
> But ++'z' isn't 'a'.
No, it is aa, the next logical thing to come after z. So, --a could be
aaaaaa..... or, to me, more logically z. But, I don't scream that my
logic is always logical ;)
> > But, why is --'a' (or any a-zA-Z) -1? Why doesn't, at least, it evaluate
> > 'a' to true (1) and --'a' = 0 (or undef, since I don't know why it
> > should return a true value)? I guess there must be a reason, but it
> > isn't documented from what I can see.
>
> Converting 'a' to a number gives 0.
I'm not convinced on that. Being that magic is built in to make a++ into
b.. so it isn't being converted to 0 in that case, which would make that
statement false. Why would it be 0?
Why not 1? Why is 'b' also converted to 0? Why not use it's ord() value?
To me (again, internal, warped, logic) --a returning ` makes more sense
than -1. z++ is aa, so why isn't aa-- reverted back to z? Why must --a
be seemingly useless?
Cheers,
Kevin
--
[Writing CGI Applications with Perl - http://perlcgi-book.com]
"Families is where out nation finds hope, where wings take dream."
-- G.W. Bush, LaCrosse, WI 10/18/2000
