On Mon, Aug 20, 2001 at 04:48:30PM -0800, Michael Fowler wrote:
> On Mon, Aug 20, 2001 at 12:21:29PM -0400, Yacketta, Ronald wrote:
> > avg1 = (value1 + values2..11) / 10
> > avg2 = (value2 + values3..12) / 10
> > avg3 = (value3 + values4..13) / 10
> >
> > the math is the easy part, how would I go about cleanly and efficiently
> > running through a has and doing the above?
>
> A hash is not the appropriate data structure for this, an array is. Adding
> all of the elements of an array is pretty straightforward: iterate over the
> array one element at a time, add that element to a total.
>
> Your "(value1 + values2 .. 11)" syntax can easily be duplicated using
> slices, e.g. @values[1..11].
Or, since you only need 10 elements, only use 10, and use % to determine
the index.
--
Paul Johnson - [EMAIL PROTECTED]
http://www.pjcj.net
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