>> >> Thanks guys. With some help I've come up with this: >> >> >> >> $string = 'abc def ghi jkl mno pqr stu vwx yz'; >> >> if(length($string) = 34) {$var1 = $string.":";} >> > >> > '=' is assignment, '==' is test for numerical equality. >> Change the above >> > line to: >> > if( length($string) == 34 ) { $var1 = $string . ':' } >> > >> >> if(length($string) > 34) { >> >> $string =~ s/\s//g; >> > >> > The above line deletes all of the spaces in $string. Is >> that what you want >> > to do? >> >> All fixed up except for this. How can I remove only the spaces at the >> end of $var1 and $var2 if they exist? >> >> - Grant >> >> >> >> ($var1, $var2) = $string =~ /(.){35}(.){26}/; >> > > This pulls 35 characters and splits words, yet what you asked for was > the last word separated. Correct?
I'm trying to pull 35 or fewer characters to the nearest space basically. This is what I have now: if(length($string) <= 34) {$var1 = $string.":";} if(length($string) > 34) { ($var1, $var2) = ($string =~ /(.{35})(.{26})/); $var1 =~ s/\s+$//; $var2 =~ s/\s+$//; $var2 .= ":"; } Does that look OK? Is the 3rd line off? - Grant -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/