Kelly Jones wrote:
I want foo() and bar() to do the same thing. One way to do this:
sub foo {return bar(@_);}
Is there a more clever way using \&bar and things like that?
$ perl -le'
use warnings;
use strict;
sub bar { print "in sub bar: @_" }
bar 1, 2, 3;
sub foo { goto &bar }
foo 4, 5, 6;
'
in sub bar: 1 2 3
in sub bar: 4 5 6
John
--
Those people who think they know everything are a great
annoyance to those of us who do. -- Isaac Asimov
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