On Wed, May 13, 2009 at 07:48, Michael Alipio <[email protected]> wrote:
>
>
> I have a c code that looks like this:
And C isn't Perl, perhaps you should ask these sort of questions on a
C list or newsgroup[1]? Or maybe Stack Overflow[2]?
snip
> However if I replace the stringcopy call arguments with "jude", "anna"
> it compiles fine but i get segmentation fault when running.
snip
Because they are string constants and you are trying to modify the
second string. You aren't allowed to do that.
snip
> How come printf can accept variable names as well as constant strings such as:
>
> printf ("%s", girl);
>
> and
>
> printf ("Hello World\n");
snip
Because printf only reads from the pointer, it doesn't modify it.
snip
> My stringcopy function only accepts pointers. Shouldn't I be passing pointer
> to the first element of "anna" when passing the string constant "anna"?? )
snip
You can point to it, but you can't modify it.
1. http://groups.google.com/group/comp.lang.c/topics
2. http://www.stackoverflow.com
--
Chas. Owens
wonkden.net
The most important skill a programmer can have is the ability to read.
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