Mark_Galeck wrote:
Why does
$foobar = \("foo", "bar");
print $$foobar;
print "bar" ??
Thank you for any insight. Mark
Because \("foo", "bar") is really (\"foo", \"bar") and the comma
operator in scalar context will return the last item listed so:
$foobar = \("foo", "bar");
Is just:
$foobar = \"bar";
John
--
The programmer is fighting against the two most
destructive forces in the universe: entropy and
human stupidity. -- Damian Conway
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