Shlomi Fish wrote:
Hi Magne,
On Tuesday 13 Apr 2010 06:35:51 Magne Sandøy wrote:
Hi.
I'm new to perl, and I stumbled across a strange behavior in my for loop.
In the following code, the second for loop actually counts way passed
what I expected, and actually stops at "yz" and not "z" as expected.
As shown by the third for loop, incrementing the letters, seems to give
me the desired output in each loop.
What is going on here?
#!/usr/bin/perl
use warnings;
use strict;
my $letter = "u";
for ("u".."z"){
print " $_ ";
}
print "\n\n";
for ($_="u"; $_ le "z"; $_++){
print " $_ ";
}
"le" is the string equivalent of "<=" (less than or equal). You probably want
"lt" instead here. A program using it yields the following:
{{
u v w x y z
u v w x y
u v w x y z aa
}}
Regards,
Shlomi Fish
print "\n\n";
for(1..7){
print " $letter ";
$letter++;
}
Hi.
So, what happened to the e in le, less than or "equal" to. In my
opinion, "z" == "yz", would be incorrect, even tough that is what
trigers the exit loop response. Try using "eq", and hopefully you
understand my frustration.
There has to be something I have misunderstood.
Brgds
Magne.
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