hi, suppose i have a string that contains n number of date patterns in the string. "2011/05/25 07:24:58 -0700 PDT 2011/04/28 XXXXXXXXXXXX 2023/23/45"
how can i extract all such patterns. On Wed, May 25, 2011 at 10:08 PM, Rob Dixon <rob.di...@gmx.com> wrote: > On 25/05/2011 15:39, Irfan Sayed wrote: > > hi, > > > > i have string like this > > "2011/05/25 07:24:58 -0700 PDT" i need to match "2011/05/25" > > i wrote reg ex like this: ^\d\d\d\d//\d\d/\d\d$ but it is not working > > > > code is like this > > > > > > $lin = "2011/05/25 07:24:58 -0700 PDT"; > > $lin =~ m/^\d\d\d\d//\d\d/\d\d$/; > > print "$lin\n"; > > > > plz suggest > > Please always write your code with 'strict' and 'warnings' in place, > especially before seeking help elsewhere. This program > > use strict; > use warnings; > > my $lin = "2011/05/25 07:24:58 -0700 PDT"; > $lin =~ m/^\d\d\d\d//\d\d/\d\d$/; > > produces the following errors: > > Backslash found where operator expected at E:\Perl\source\ps.pl line 5, > near "d\" > Backslash found where operator expected at E:\Perl\source\ps.pl line 5, > near "d\" > syntax error at E:\Perl\source\ps.pl line 5, near "d\" > Execution of E:\Perl\source\ps.pl aborted due to compilation errors. > > And tells you immediately that there is something wrong with your regex. > > Cheers, > > Rob > > -- > To unsubscribe, e-mail: beginners-unsubscr...@perl.org > For additional commands, e-mail: beginners-h...@perl.org > http://learn.perl.org/ > > >
