At 10:41 AM +0800 3/23/12, lina wrote:
On Fri, Mar 23, 2012 at 10:20 AM, John W. Krahn <jwkr...@shaw.ca> wrote:
John W. Krahn wrote:
$ echo "Hr 12
0001 2
0002 3
0003 1
Hr 13
0001 2
0002 3
0003 1
Hr 14
0001 2
0002 3
0003 1" | perl -e'
my ( @hours, %data );
while ( <> ) {
push @hours, $1 if /^hr\s*(\d+)/i;
$data{ $1 }{ $hours[ -1 ] } = $2 if /^(\d+)\s+(\d+)/;
}
print join( "\t", "", @hours ), "\n";
for my $row ( sort { $a <=> $b } keys %data ) {
print $row;
for my $col ( sort { $a <=> $b } keys %{ $data{ $row } } ) {
print "\t$data{$row}{$col}";
}
print "\n";
}
'
12 13 14
0001 2 2 2
0002 3 3 3
0003 1 1 1
Probably better:
$ echo "Hr 12
0001 2
0002 3
0003 1
Hr 13
0001 2
0002 3
0003 1
Hr 14
0001 2
0002 3
0003 1" | perl -e'
my ( @hours, %data );
while ( <> ) {
push @hours, $1 if /^hr\s*(\d+)/i;
$data{ $1 }{ $hours[ -1 ] } = $2 if /^(\d+)\s+(\d+)/;
}
print join( "\t", "", @hours ), "\n";
for my $row ( sort { $a <=> $b } keys %data ) {
print $row;
for my $col ( @hours ) {
print "\t$data{$row}{$col}";
}
print "\n";
}
'
12 13 14
0001 2 2 2
0002 3 3 3
0003 1 1 1
Here I use:
push @hours, $1 if(/Hr\b(.*)\b/) ;
$data{$1}{$hours[-1]} = $2 if(/\b(.+)\b(.*)\b/);
it reported, how can I fix it:
By using the correct regex. You need to use \d or [0-9] in your
regular expression rather than the dot character, which matches any
character. You are matching and capturing the entire line with (.+),
leaving nothing for the second capture group.
$ perl calen.pl
12 13 14
Argument "0003 1" isn't numeric in sort at calen.pl line 23,
<$_[...]> line 12.
Argument "0002 3" isn't numeric in sort at calen.pl line 23,
<$_[...]> line 12.
Argument "0001 2" isn't numeric in sort at calen.pl line 23,
<$_[...]> line 12.
Argument "Hr 12" isn't numeric in sort at calen.pl line 23, <$_[...]> line 12.
Argument "Hr 13" isn't numeric in sort at calen.pl line 23, <$_[...]> line 12.
Argument "Hr 14" isn't numeric in sort at calen.pl line 23, <$_[...]> line 12.
Hr 12 Hr 13 Hr 14 0001 2 0002 3 0003 1l
Thanks,
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Jim Gibson
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