""Chris Charley"" wrote in message
"Chris Stinemetz" wrote in message news
Hello List,
I have input data such as far below:
I would like to read the data into an array and modify the 2nd index if
the
0th and first indices are identical.
I would like the updated 2nd index to be an average of the 2nd index where
both occurences of 0th and 1st indices match.
[snip question]
Hi Chris,
[snip verbose answer]
I engaged fingers before my brain. :-(
No need to make 2 passes to solve this problem. A one pass solution proved
to be more concise and conserved resources (compared to the 2 pass
solution).
#!/usr/bin/perl
use strict;
use warnings;
use List::Util qw/ sum /;
my %data;
my ($col0, $col1, @rest) = split ' ', <DATA>;
push @{ $data{$col0, $col1} }, \@rest;
while (<DATA>) {
my ($col0, $col1, @rest) = split;
my $key = "$col0$;$col1";
if (exists $data{$key}) {
push @{ $data{$key} }, \@rest;
}
else {
print_it(%data);
undef %data;
push @{ $data{$key} }, \@rest;
}
}
print_it(%data);
sub print_it {
my ($comp_key, $aref) = @_;
my $avg = sprintf "%.f", sum( map $_->[0], @$aref ) / @$aref;
my ($col0, $col1) = split /$;/, $comp_key;
for my $i (0 .. $#$aref) {
print join(" ", $col0, $col1, $avg, $aref->[$i][1]), "\n";
}
}
__DATA__
22 1 60 65
22 2 180 90
22 3 300 90
23 1 0 65
23 2 90 65
23 3 260 65
24 1 60 65
24 1 40 65
24 2 180 65
24 2 160 65
. . . .
Chris
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