> s/(i)(\d\d)(o)/1$20/;
You don't need to capture the "i" or "o"
s/i(\d+)o/1${1}0/
If there were more i or o's, 2 subs
s/i/1/g
s/o/0/g
The "g" globally replacing all the matches. There's probably a tricky way to
do that in one but.
> Since you are capturing 3 groups:
s/(i)([0-9]{2})(o)/$1$2$3/;
Er, bit of a no-op there ;->
s/(i)([0-9]{2})(o)/1${2}0/;
a
Andy Bach
(608) 658-1890
Not at my desk
On Jan 3, 2013, at 2:22 AM, "Dr.Ruud" <rvtol+use...@isolution.nl> wrote:
> On 2013-01-02 15:34, Hamann, T.D. wrote:
>
>> [...] given a string:
>>
>> i99o
>>
>> where I want to replace the 'i' by a '1' and the 'o' by a '0' (zero), the
>> following regex fails:
>>
>> s/(i)(\d\d)(o)/1$20/;
>
> Since you are capturing 3 groups:
>
> s/(i)([0-9]{2})(o)/$1$2$3/;
>
>
>>
>> for the obvious reason that perl looks for a pattern match at bracket set
>> #20, which doesn't exist.
>>
>> I can fix this by inserting a space in front of the zero, like this:
>>
>> s/(i)(\d\d)(o)/1$2 0/;
>>
>> and then using a second regular expression to remove the space, but that
>> somehow seems silly. Surely there is a quicker way to do this?
>>
>> Regards,
>> Thomas Hamann
>
>
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