On Sat, Jan 25, 2014 at 4:12 PM, Paul Johnson <p...@pjcj.net> wrote:
> $ perl -E '$h = { a => qr/y/ }; say $_ =~ $h->{a} for qw(x y z)'
Thanks, but then another doubt: having a look at
http://perldoc.perl.org/perlop.html#Regexp-Quote-Like-Operators I dont
understand how I can use the regexp for substitution, that is s/// as
an hash value. The following is not working:
my $hash = { q/regexp/ => qr/s,from,to,/ };
any clue?
THanks,
Luca
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