On Wed, 6 May 2015 12:49:53 +0530
Anirban Adhikary <[email protected]> wrote:
> Hi List
> I have the following array ---
> ('1900-0','1900-1','NULL','NULL','1900-2','1900-4','1902-5','1902-6','1902-7','1902-8');
> There are two part for each element separated by a dash.
> first one known as earfcn and second one is pcid .
> The requirement is For the same “earfcn”, concatenate the “pcid”
> values using "&" separator between values.
> so the output will be like this
> EARFCN=1900,PCID=0&1&2&4;
> EARFCN=1902,PCID=5&6&7&8;
>
> I am not able to generate any idea how to adress this isuue. Please
> give me some starting point.
>
> Best Regards
> Anirban.
Unlike everyone else, I would used nested hashes. Why? Because then the
code can hand duplicates.
#!/usr/bin/env perl
use strict;
use warnings;
my @data =
('1900-0','1900-1','NULL','NULL','1900-2','1900-4','1902-5','1902-6','1902-7','1902-8');
my %hash = ();
# load the data structure
for my $item ( @data ){
if( my ( $earfcn, $pcid ) = $item =~ m{ \A ( \d+ ) \- ( \d+ ) \z }msx ){
$hash{$earfcn}{$pcid} ++;
}
}
# output the data
for my $earfcn ( sort { $a <=> $b } keys %hash ){
my @pcids = ();
for my $pcid ( sort { $a <=> $b } keys %{ $hash{$earfcn} } ){
for my $count ( 1 .. $hash{$earfcn}{$pcid} ){
push @pcids, $pcid;
}
}
print "EARFCN=$earfcn,PCID=", join( q{&}, @pcids ), "\n";
}
--
Don't stop where the ink does.
Shawn
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