this code just returns a reference to a scalar, which is rather pointless in
this case and really doesn't solve the problem.
> sub return_scalars {
> $scal1 = 5; Assign values to scalars somehow
> $scal2 = 7;
> return \$scal1, \$scal2;
> }
>
> ($test_scalar1, $test_scalar2) = &return_scalars();
you can do 2 things in this case:
1: get a list of scalars returned #which can be treated as an array by
the caller
2: get a reference to a list of scalars returned.
1:
sub gimme {
return ( 'foo', 'bar', 'bleh' )
}
2:
sub gimme {
return [ 'foo', 'bar', 'bleh' ]
}
the benefit of 2 is that you get a scalar returned (since references are
just special scalars really).
you could access the element 'bar' like this:
my $array_ref = gimme();
my $val = $array_ref->[1];
it's often wise to just pass around references.
if you want to know more about the why and how, take a look at
http://japh.nu and read the tutorial on references.
hth,
Jos
> -----Original Message-----
> From: Roy Peters [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, October 31, 2001 7:44 AM
> To: [EMAIL PROTECTED]
> Subject: returning more than 1 scalar from a subroutine
>
>
> hi,
>
> Is there any way to return 2 or 3 scalar variables from a subroutine (like
> passing a variable by reference in C)?
>
> I would like to avoid returning an array, if possible, because it makes
> the script very non-intuitive.
>
> Thanks
>
>
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