$#array is the index of the last element of @array, so it will be one less than scalar @array which is the number of elements in @array (since Perl arrays start with index 0). Therefore, to get the number of elements, you would need to add one to $#array, which makes scalar @array faster. To get the last index you would need to say @array - 1, which would make $#array faster.
On Sun, Jan 28, 2018, 13:39 Peng Yu <pengyu...@gmail.com> wrote: > Hi, > > For the following two expressions, are they of the same speed or one > of them is faster? > > `$#array` vs `scalar @array` > > -- > Regards, > Peng > > -- > To unsubscribe, e-mail: beginners-unsubscr...@perl.org > For additional commands, e-mail: beginners-h...@perl.org > http://learn.perl.org/ > > >
