> On Nov 24, 2018, at 12:49 PM, David Precious <dav...@preshweb.co.uk> wrote:
>
> I went to perldoc perlop expecting to be able to find a
> section to point the OP at as a "here's the documentation for it", and
> couldn't find anything particularly useful.
I was able to find this in “perldoc perlop”:
Assignment Operators
"=" is the ordinary assignment operator.
Assignment operators work as in C. That is,
$x += 2;
is equivalent to
$x = $x + 2;
although without duplicating any side effects that dereferencing the
lvalue might trigger, such as from "tie()". Other assignment operators
work similarly. The following are recognized:
**= += *= &= &.= <<= &&=
-= /= |= |.= >>= ||=
.= %= ^= ^.= //=
x=
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