On Nov 15, Adam Turoff said: >Find the first day of the next month (remember december/january rollover) >and subtract one day:
> my ($mon, $year) = (11, 2001); > my $first = timelocal(0,0,0, 1, $mon % 12, ($year-1900 + int($mon/12))); You'll probably want to use noon if you're going to subtract days. It's safer in general, and I should have done it to begin with. And I'd use $mon == 12 instead of int($mon/12) because it's a bit less obfuscated. Then again, you probably don't even NEED the int() there. -- Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/ RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/ ** Look for "Regular Expressions in Perl" published by Manning, in 2002 ** -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
