On Tue, 27 Nov 2001, Jorge Goncalvez <[EMAIL PROTECTED]> wrote,
> Hi I have this:
>
> my $ip="192.40.54.41";
>
> $ip=~ s/(\d+\.\d+)\.(\d+\.\d+)/$1\.0/;
>
> print $ip;
>
> But It didn't work it displays 192.40.0 and I wanted to display 192.40.54.0.
> Why? thanks.
The first parentheses (refered to by $1) already contain 192.20. The first
\d+ (one digit or more) matches 192, the \. matches the first ., and the
second \d+ matches 40. So $1 contains "192.40".
If you know exactly you'll change the the *last* sequence, you want to
change only that.
$ip =~ s/\d{1,3}$/0/;
san
--
Trabas - http://www.trabas.com
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
