Hi Messier,

Try that:

#[1]
$str="206.48.16.3/12345";
$str=~ s/\/.*//g;

#[2]
$str="src=206.48.16.3/12345";
$str=~ s/^src=|\/.*//g;


I hope that helps.

--Ahmed
[EMAIL PROTECTED] | http://arbornet.org/~ahmed

On Thu, 6 Dec 2001, Messier, Jean-Francois wrote:

>       I'm a beginner in those regular expressions and s/// operations. How
> can I extract only the digits and the periods (.) from a string ? I have
> something like 206.48.16.3/12345. An IP address with a port number. There
> are digits on both sides of the slash, but I would like to keep only the
> digits from on the left as well as the periods. More complex question: If I
> have something like "src=206.48.16.3/12345", how can I do the same as bove,
> but also removing the "src=" at the beginning ?
> 
>       Thanks :-)
> 
> Jean-Francois Messier
> Ottawa, CANADA
> 
> -----Original Message-----
> From: Jeff 'japhy' Pinyan [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, December 05, 2001 11:18 PM
> To: Daniel Falkenberg
> Cc: [EMAIL PROTECTED]
> Subject: Re: Confirmation...
> 
> 
> On Dec 6, Daniel Falkenberg said:
> 
> >$string =~ s/[^a-zA-Z0-9]//g;
> >
> >I take it only allows $string to eq anthing in the charcter class of
> >a-z, A-Z and 0-9.  I also take it that anything other than that will be
> >stripped out?  Any other comments?
> 
> Right.  I'd write it as
> 
>   s/[^a-zA-Z0-9]+//g;
> 
> for "efficiency".  Or perhaps as
> 
>   tr/a-zA-Z0-9//cd;
> 
> for "clarity".  Your ideas of "efficiency" and "clarity" may differ.
> 
> -- 
> Jeff "japhy" Pinyan      [EMAIL PROTECTED]      http://www.pobox.com/~japhy/
> RPI Acacia brother #734   http://www.perlmonks.org/   http://www.cpan.org/
> ** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
> <stu> what does y/// stand for?  <tenderpuss> why, yansliterate of course.
> 
> 
> -- 
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