>
>
>But how could I take two arguments from the command line:
>
>i.e. my guess:
>
>%Test.pl "Foo" "Bar"
>
>#/!/usr/bin/perl
> $A = $ARGV[0];
> $B = $ARGV[1];
> print "Thing A: $A Thing B: $B";
>
I think you already answered your own question! Though your shebang
line should be "#!/usr/bin/perl".
Other ways of doing this are:
#!/usr/bin/perl
($A, $B) = @ARGV;
#!/usr/bin/perl
use strict;
# Lets be strict and explicitly declare $A and $B.
my ($A, $B) = @ARGV;
#!/usr/bin/perl
use strict;
# After this @ARGV will be two elements shorter.
# if @ARGV contains ('foo.txt','bar.txt','another.txt','yetanother.txt') now
my $A = shift @ARGV;
my $B = shift @ARGV;
# then @ARGV contains ('another.txt','yetanother.txt') now.
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