On Jan 29, [EMAIL PROTECTED] said: >I am sure we could do it in one step as this: > $str =~ s/(\d\d\s*)$/$1;
No, that's missing the last /, and all it does is replace what it matches with itself. ($str) = $str =~ /(\d\d\s*)$/; works, though. >> $str =~ /(\d\d\s*)$/; >> $str = $1; This runs the risk of assigning something COMPLETELY foreign to $str, because if the regex fails, $1 will hold what it held before the regex. Mine will assign undef to $str if the regex fails. -- Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/ RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/ ** Look for "Regular Expressions in Perl" published by Manning, in 2002 ** <stu> what does y/// stand for? <tenderpuss> why, yansliterate of course. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
