>>>>> "Randal" == Randal L Schwartz <[EMAIL PROTECTED]> writes:
>>>>> "Robert" == Robert Hanson <[EMAIL PROTECTED]> writes:
Robert> You probably want to use "map".
Robert> This should work.
Robert> @body = map { s/foo/bar/; $_ } (@body);
Randal> No. Please don't answer without testing.
Randal> That messes up @body as well, since $_ is an alias back into the
Randal> original list.
And of course, I need to read better. :) I was thinking it was
@new = map { s/foo/bar; $_ } @body;
So Robert's solution was just plain wierd, although it will do the
job. It's a bit like saying "$a = $a = 3 + $b". Why the second
assignment? :)
Randal> This works:
Randal> s/foo/bar/ for @body;
Randal> presuming you have a reasonably modern Perl.
And can read your own handwriting. :)
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