([^=]+) goes into $1
(.*) goes into $2
Unless the parens are escaped(ie, \( ), you count from the left where the
first ( is $1, 2nd is $2 ,etc. They can be nested if necessary.
Wags ;)
-----Original Message-----
From: Batchelor, Scott [mailto:[EMAIL PROTECTED]]
Sent: Thursday, May 09, 2002 11:55
To: [EMAIL PROTECTED]
Subject: RE: Pattern Matching...
Ok, Sorry guys I am trying to get my head around this...
$pair=~m/([^=]+)=(.*)/)
The "m" means treat string as multiple lines
Then we are grouping with a parenthesis and the "^=" is saying matching
anything up to the "="
The "+" is a quantifier saying that must match 1 or more times...
Then the the rest is saying match anything after the "="
I guess my question is am I right?
And I still am not sure where it is saying to assign the first match to
variable $1 and then the rest to variable $2
Thanks in advance...
Scott
-----Original Message-----
From: Felix Geerinckx [mailto:[EMAIL PROTECTED]]
Sent: Thursday, May 09, 2002 12:38 PM
To: [EMAIL PROTECTED]
Subject: Re: Pattern Matching...
on Thu, 09 May 2002 17:33:21 GMT, Scott Batchelor wrote:
> $pair=~m/([^=]+)=(.*)/)
>
> This basically says start at the beginning of the string and match
> any "=" all the way to the end of the string...right?
Wrong.
This says:
Match anything (of at least one character) up to but not including '=' and
put it in the special variable $1; then match the '='; then match what's
left (possibly nothing) and put it in the special variable $2.
--
felix
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