On May 10, FLAHERTY, JIM-CONT said:
>This string can be various in length ? Note it doesnt end with that
>delimiter. Help
>
> $jims = "!23!45!67
You could use split(), but you'd have to get rid of the first
(empty) element. Instead, I would suggest the following regex:
while ($string =~ /!([^!]*)/g) {
my $num = $1;
# ...
}
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
<stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
[ I'm looking for programming work. If you like my work, let me know. ]
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