^ -> Beginning o the string $ -> End of the string $myVar =~ s/^\s+//; -> Remove all Leading White Space $myVar =~ s/\s+$//; -> Remove all Trailing White Space
What is your actual requirement ?? -----Original Message----- From: Alaric Joseph Hammell [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 11, 2002 4:54 PM To: [EMAIL PROTECTED] Subject: Re: chop off 1 white space? At 01:34 PM 6/11/02 -0700, I wrote: >At 04:26 PM 6/11/02 -0400, Alaric Joseph Hammell wrote: > >>How would I get rid of one trailing white space character in >>$HASH{$key} and reassign the result > >If you're certain that the last character is a space: > > chop $HASH{$key}; > >If it might not be a space, and you only want to get rid of the last >character if it is a space: > > $HASH{$key} =~ s/ $//; >Oops, I missed the "white" part of "white space". Then the question >is >whether you intend "white space" to include newline. Assuming you >don't >(which is Perl's definition of "white space"), then: > > $HASH{$key} =~ s/\s$//; Ok, What I meant by "match" was "compare" or test for equality. Sorry for the confusion. But, could someone explain the meaning of the "$" in the above expression, s/\s$// . How would I incorporate in the expression the $string which occurs before the white space? (is that what the "$" is for?) Thank you for all the helpful responses, Al -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
