> > On Wednesday, June 26, 2002, at 08:48 AM, Shishir K. Singh wrote: > > >> $out = $1 if ($in =~ /\((.*?)\)/); > > Nope..won't work..I take it back!! > > > > >looks ok to me. except it adds extra strokes to previous answer. > >what do you think is wrong with it? > > It will work fine as far as the regex is concerned. I think > what Todd may want is to check the $out for defined or > undefined. This line won't give him the same kind of validation. > > > Perhaps..he should be doing it this way > > $in =~ /\((.*?)\)/; > $out = (defined($1) ? $1 : "default/undef/whatever??";
>Sorry, still not right. defined($1) is no better than $1 alone after >a failed match. >Again, the most straightforward solution is: > ($out) = $in =~ /\((.*?)\)/; You are right ...this will be the the most simple sol..in case nothing needs to be done to $out...but in case some thing needs to be done on $out which I am assuming to be true, then the value of $out needs to be checked again, which introduces additional lines and variable declaration. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
