>Thanks! Changing: >my $message = @_; >to: >my ($message) = @_;
>did put the correct value in the string. >If anyone cares to explain the difference between the code I had and the code >Shishir suggested so I can understand why this makes a difference, I'm all >ears! @_ is an array. You were trying to do "my $message = @_;" Here $message will get the scalar value of the array i.e the number of elements in the array..which you are rightfully getting = 1. my ($message) = @_; ## This takes the value from @_ in array context and since there is only one element in @_, therefore, only one variable on the left side in array context is needed. Hence "my ($message) = @_;" you could have used my $message = shift; or my $message = $_[0]; -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
