On Wed, 28 Aug 2002, Angerstein wrote: > Than its possible: > my $x = 0; > > my @arr1 = (1, 2, 3); > > my @arr2 = (4, 5, 6); > > my @arr3 = (7, 8, 9); > > my @arrofarrs; > > unshift (@arrofarrs, \@arr3); > > unshift (@arrofarrs, \@arr2); > > unshift (@arrofarrs, \@arr1); > unshift (@arr1, $x); > > and it will be in @arrofarrs. > > right?
Yes, that is right? If you have any doubts about your data structure Data::Dumper is your friend. perldoc Data::Dumper -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
