On Oct 3, [EMAIL PROTECTED] said:
>I'm having a difficult time understanding the map function.
You're having a hard time coping with the fact that $_ is an alias to the
values in the list you're mapping over, not a copy.
>@new_names = map { ($x = $_) =~ s/(jpg|gif)$/html/i; $x } @old_names;
>
>Is there a more elegant way to accomplish this? It just doesn't seem
>elegant assigning $_ to $x, performing the substitution on $x, and then
>returning $x.
Sure:
# no need to do two statements:
# @new = @old;
# ... for @new;
# just do it all at once:
s/(jpg|gif)$/html/i for @new_names = @old_names;
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
<stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
[ I'm looking for programming work. If you like my work, let me know. ]
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